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-27a+3a^2+46=0
a = 3; b = -27; c = +46;
Δ = b2-4ac
Δ = -272-4·3·46
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{177}}{2*3}=\frac{27-\sqrt{177}}{6} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{177}}{2*3}=\frac{27+\sqrt{177}}{6} $
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